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Heat Transfer Co-Efficient Calculation

Autor:   •  February 10, 2018  •  1,125 Words (5 Pages)  •  756 Views

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Prandtl Number:

Equation 5[pic 15]

Reynold's Number:

Equation 6[pic 16]

Nusselt Number:

Equation 7[pic 17]

Using the above equations (5, 6 and 7):

For Cooling water:

Prandtl Number, Prcw = = = 4.981[pic 18][pic 19]

Reynold's Number, Recw = = = 48.318[pic 20][pic 21]

Nusselt Number. Nucw = = 6.146[pic 22]

Similarly, for product:

Prandtl Number, Prp = 4.527

Reynold's Number, Rep = 49.131

Nusselt Number, Nup = 5.979

Nusselt number can also be defined as:

Equation 8[pic 23]

where, h = film heat transfer co-efficient

Rearranging equation 8 in terms of h, gives:

Equation 9[pic 24]

Using the above equation the film transfer co-efficient for cooling water and product can be found as follows:

For cooling water, hcw = = = 449.32 Wm-2 °C-1[pic 25][pic 26]

Similarly for product, hp = 441.46 Wm-2 °C-1

The overall heat transfer co-efficient for the heat exchanger (UPHE1) can be calculated using the following equation (Coulson and Richardson Volume 6, Chapter 12):

Equation 10[pic 27]

All the values on the right hand side of equation 10 have been calculated above, as shown. Putting in these values and rearranging in terms of UPHE1 :

Overall heat transfer co-efficient, UPHE1 = [pic 28]

= 207.54 W m-2 °C-1

The heat transfer co-efficient have been calculated for old and new heat exchangers. The exchangers are compared and results analysed in the discussion section below.

For Coil in Reactor RV1

Table 2 Technical and Physical Data for Coil

Parameters

Notation

Units

Value

Internal Diameter Tube

di

Mm

4

Given

M

0.004

Internal Coil Area

Ai

m2

1.26E-05

=(π*di2)/4

Thickness of Tube

tt

Mm

1

Outside Diameter tube

do

Mm

6

=di+(2*tt)

M

0.006

Outside Coil Cross Sectional Area

Ao

m2

2.83E-05

Average Coil Diameter

dav

M

0.005

Length of Paddle

L

Cm

40

M

0.4

Turns of Coils

Nt

18

Thermal Conductivity Stainless Steel

Kw

W m-1C-1

16.7

Coil Width

dc

Cm

50

Number of Revolutions

N

rev/s

1

Assumed

Flow Rate Through Coil

F

l/min

5

Assumed

m3/s

8.33E-05

Velocity Through the Tube

u

m/s

6.63

=F/Ai

Reactor Diameter

dr

M

0.75

Equivalent Straight Length of Coil

Le

M

28.27

=π*dc*Nt

Total Heat Transfer Area

Aht

m2

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