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Autor:   •  January 29, 2018  •  792 Words (4 Pages)  •  548 Views

Page 1 of 4

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7) > samplebmi1

> samplebmi1

[1] 22.61519 30.68702 27.99801 24.86513 24.74188 27.86049 26.45994 28.09394

[9] 24.90291 24.92058 19.23282 28.64422 29.32497 21.41803 21.89220 32.72707

[17] 23.71241 27.39722 22.11940 21.41484 25.52571 21.85916 24.13166 26.23878

[25] 22.98395 24.16282 26.22704 28.38939 35.18590 24.64068 20.07044 26.90325

[33] 28.49141 26.86607 25.92871 25.20929 23.10816 32.24865 21.46042 24.39974

[41] 25.73905 31.21014 20.74159 29.64699 22.79580 29.83458 30.42022 22.72962

[49] 38.57049 27.88062 27.09845 34.45011 21.62722 30.22772 25.39119 25.38602

[57] 23.19926 20.11476 18.18159 29.87958 23.90303 28.89880 28.30629 25.52927

[65] 26.06227 17.92705 27.24941 27.34853 23.72921 19.09993 21.62604 25.10457

[73] 20.21998 26.09249 26.40898 21.35310 30.23275 24.59962 27.16169 25.27255

[81] 22.97916 26.52632 23.15445 29.13450 32.18537 24.13060 28.50459 26.17230

[89] 23.37700 20.54472 31.03960 20.97464 19.71637 23.76860 22.73930 32.84538

[97] 29.77436 31.93939 26.20482 20.17837

> mean(samplebmi1)

[1] 25.722

> sd(samplebmi1)

[1] 3.983918

(yes it does have the mean of the population)

Null Hypothesis

- H0 = there is no difference between the mean of samplebmi1 and the meanbmi

- Research Hypothesis

H1 = there is a difference between the mean of samplebmi1 and the meanbmi

> t.test(samplebmi1,conf.level=0.95)

One Sample t-test

data: samplebmi1

t = 64.565, df = 99, p-value

alternative hypothesis: true mean is not equal to 0

95 percent confidence interval:

24.93150 26.51249

sample estimates:

mean of x

25.722

> t.test(samplebmi1,mu=bmimean,conf.level=0.95)

One Sample t-test

data: samplebmi1

t = 1.8513, df = 99, p-value = 0.06711

alternative hypothesis: true mean is not equal to 24.98446

95 percent confidence interval:

24.93150 26.51249

sample estimates:

mean of x

25.722

Therefore H0 = there is no difference between the mean of samplebmi1 and the meanbmi

8a) > pnorm(38,agemean,agesd)-pnorm(32,agemean,agesd)

[1] 0.5262774

b) > qnorm(0.9,agemean,agesd)

[1] 40.34255

9a) > pfemale.hat

> pfemale.hat

[1] 0.50032

b) > pfemale.hat-1.96*sqrt(pfemale.hat*(1-pfemale.hat)/n)

[1] 0.497221

> pfemale.hat+1.96*sqrt(pfemale.hat*(1-pfemale.hat)/n)

[1] 0.503419

Confidence level is between 0.497221 to 0.503419

10) pnormal.hat

> pnormal.hat-1.96*sqrt(pnormal.hat *(1- pnormal.hat)/n)

[1] 0.6736907

> pnormal.hat+1.96*sqrt(pnormal.hat *(1- pnormal.hat)/n)

[1] 0.6794893

Confidence level is between 0.6736907 to 0.6794893

11) a) > systolic

> group

> tapply(systolic,group,mean)

HIGH LOW NORMAL

139.5428 101.0527 120.4786

b)> diastolic

> tapply(diastolic,group,mean)

HIGH LOW NORMAL

97.66724 55.35062 76.66577

c)> tapply(systolic,group,sd)

HIGH LOW NORMAL

7.868794 4.574340 7.710230

b)> tapply(diastolic,group,sd)

HIGH LOW NORMAL

7.278075 4.021760 7.489079

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